Can I use variadic templates without using the template parameters as function parameters?
When I use them, it compiles:
#include <iostream>
using namespace std;
template<class First>
void print(First first)
{
cout << 1 << endl;
}
template<class First, class ... Rest>
void print(First first, Rest ...rest)
{
cout << 1 << endl;
print<Rest...>(rest...);
}
int main()
{
print<int,int,int>(1,2,3);
}
But when I don't use them, it doesn't compile and complains about an ambiguity:
#include <iostream>
using namespace std;
template<class First>
void print()
{
cout << 1 << endl;
}
template<class First, class ... Rest>
void print()
{
cout << 1 << endl;
print<Rest...>();
}
int main()
{
print<int,int,int>();
}
Unfortunately the classes I want to give as template parameters are not instantiable (they have static functions that are called inside of the template function).
Is there a way to do this?
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